reorder byte order in hex string (python)

Question

I want to build a small formatter in python giving me back the numeric values embedded in lines of hex strings.

It is a central part of my formatter and should be re

Answer 1

This should do exactly what unutbu's version does, but might be slightly easier to follow for some...

from binascii import unhexlify
from struct import pack, unpack
orig = unhexlify('b62e000052e366667a66408d')
swapped = pack('<6h', *unpack('>6h', orig))
print unpack('

Basically, unpack 6 shorts big-endian, repack as 6 shorts little-endian.

Again, same thing that unutbu's code does, and you should use his.

edit Just realized I get to use my favorite Python idiom for this... Don't do this either:

orig = 'b62e000052e366667a66408d'
swap =''.join(sum([(c,d,a,b) for a,b,c,d in zip(*[iter(orig)]*4)], ()))
# '2eb60000e3526666667a8d40'