C++ virtual inheritance initializer list

Question

in the following code:

class A
{
public:
    int x;
    A(int x):x(x){}
};

class B: public virtual A
{
public:
    B(int x):A(x){}
};
class C: public virtua         


        

Answer 1

Why do I need to add A(...) in D's initializer list?

That's because virtual base subobjects must be initialized before all other subobjects. Since A does not have a default constructor, you need to initialize the virtual A subobject in D explicitly and specify which argument you want it to be constructed with.

When the constructors of the B and C base subobjects are executed, they won't have a base A subobject to initialize (that has been done before already). Therefore, the arguments they pass to A's constructor are irrelevant.

D(int x):B(x++), C(x++), A(x++){} and D(int x):A(x++), B(x++), C(x++){} both give the same result with cout<, why?

As explained above, that's because virtual base subobjects are initialized first anyway.

In general, the order of initialization of a class's subobjects never depends on the order in which they appear in your constructor's initialization list. Per paragraph 12.6.2/10 of the C++11 Standard:

In a non-delegating constructor, initialization proceeds in the following order:

— First, and only for the constructor of the most derived class (1.8), virtual base classes are initialized in the order they appear on a depth-first left-to-right traversal of the directed acyclic graph of base classes, where “left-to-right” is the order of appearance of the base classes in the derived class base-specifier-list.

— Then, direct base classes are initialized in declaration order as they appear in the base-specifier-list (regardless of the order of the mem-initializers).

— Then, non-static data members are initialized in the order they were declared in the class definition (again regardless of the order of the mem-initializers).

— Finally, the compound-statement of the constructor body is executed.