How to fill a list

Question

I have to make a function that takes an empty list as first argument and n as secound argument, so that:

L=[]
function(L,5)
print L
returns:
[1,2,3,4,5]
         


        

Answer 1

In

def fillList(listToFill,n):
    listToFill=range(1,n+1)

you change only the pointer of listToFill, if you don't return the new pointer; the new pointer isn't available out of the function and you have still the pointer of your empty list (in outer scope).