Converting List of 3 Element Tuple to Dictionary

Question

If I have two List of tuples

tuple2list=[(4, 21), (5, 10), (3, 8), (6, 7)]

tuple3list=[(4, 180, 21), (5, 90, 10), (3, 270, 8), (6, 0, 7)]

Answer 1

This pair-case is simple, since it aligns with dict construction:

... the positional argument must be an iterator object. Each item in the iterable must itself be an iterator with exactly two objects. The first object of each item becomes a key in the new dictionary, and the second object the corresponding value.

>>> t = [(4, 21), (5, 10), (3, 8), (4, 7)]
>>> dict(t)
{3: 8, 4: 7, 5: 10}

The triple case could be solved in this way:

>>> t = [(4, 180, 21), (5, 90, 10), (3, 270, 8), (4, 0, 7)]
>>> dict([ (k, [v, w]) for k, v, w in t ])
{3: [270, 8], 4: [0, 7], 5: [90, 10]}

Or a bit more general:

>>> dict([ (k[0], k[1:]) for k in t ]) # hello car, hi cdr
{3: (270, 8), 4: (0, 7), 5: (90, 10)}

Note that your code:

_3_tuplelist_to_dict = {4: {180:21}, 5:{90:10}, 3:{270:8}, 4:{0:7}}

is really just a confusing representation of this:

{3: {270: 8}, 4: {0: 7}, 5: {90: 10}}

Try:

>>> {4: {180:21}, 5:{90:10}, 3:{270:8}, 4:{0:7}} == \
    {3: {270: 8}, 4: {0: 7}, 5: {90: 10}}
True

With Python 3, you can use a dict comprehension:

>>> t = [(4, 180, 21), (5, 90, 10), (3, 270, 8), (4, 0, 7)]
>>> {key: values for key, *values in t}
{3: [270, 8], 4: [0, 7], 5: [90, 10]}