Access the UIPageControl created by iOS6 UIPageViewController?

Question

I\'m using a UIPageViewController with Navigation set to Horizontal, Transition Style set to Scroll (in InterfaceBuilder), and no spine. Which gives me a lovely

Answer 1

I implemented a category to handle this for me which gets the mess out of my code and allows me to access the pageControl via "pageController.pageControl"

Objective-C

// Header
@interface UIPageViewController (PageControl)

@property (nonatomic, readonly) UIPageControl *pageControl;

@end

I also used recursion (handled by blocks) in case Apple decides to change the implementation causing the UIPageControl to not be in the first layer of subviews.

// Implementation
#import "UIPageViewController+PageControl.h"

@implementation UIPageViewController (PageControl)

- (UIPageControl *)pageControl
{
    __block UIPageControl *pageControl = nil;
    void (^pageControlAssignBlock)(UIPageControl *) = ^void(UIPageControl *blockPageControl) {
        pageControl = blockPageControl;
    };

    [self recurseForPageControlFromSubViews:self.view.subviews withAssignBlock:pageControlAssignBlock];

    return pageControl;
}

- (void)recurseForPageControlFromSubViews:(NSArray *)subViews withAssignBlock:(void (^)(UIPageControl *))assignBlock
{
    for (UIView *subView in subViews) {
        if ([subView isKindOfClass:[UIPageControl class]]) {
            assignBlock((UIPageControl *)subView);
            break;
        } else {
            [self recurseForPageControlFromSubViews:subView.subviews withAssignBlock:assignBlock];
        }
    }
}

@end

This may be overkill for your needs but it worked well for mine