Local function declaration inside namespace

Question

In such a situation

namespace n {
    void f() {
        void another_function();
    }
}

Should the function another_function

Answer 1

C++11 3.5 (as well as C++03)

7 When a block scope declaration of an entity with linkage is not found to refer to some other declaration, then that entity is a member of the innermost enclosing namespace. However such a declaration does not introduce the member name in its namespace scope.

The declaration in your example declares n::another_function.