How is the == operator implemented in Java?

Question

Specifically, in the case of object reference equality, what does the == operator do?

Does the comparison return true if the references evaluate to the same object a

Answer 1

The == operator returns true if the objects are the same object. There is not access to hashCode() or equals() here.

Try this to confirm:

public class Test {
    static void testEqualEqual(Integer I0, Integer I1, boolean IsEquals) {
        if(!(IsEquals == (I0 == I1)))
            throw new AssertionError();
    }
    static void testEqual(Integer I0, Integer I1, boolean IsEquals) {
        if(!(IsEquals == (I0.equals(I1))))
            throw new AssertionError();
    }
    static void testHash(Integer I0, Integer I1, boolean IsEquals) {
        if(!(IsEquals == (I0.hashCode() == I1.hashCode())))
            throw new AssertionError();
    }

    public static void main(String ... args) {
        testEqualEqual(   1,    1, true);
        testEqualEqual(2000, 2000, false);

        testEqual(   1,    1, true);
        testEqual(2000, 2000, true);

        testHash(   1,    1, true);
        testHash(2000, 2000, true);
        System.out.println("Done");
    }
}

To understand this, you should know first that the number number 255 will be cached when autoboxed. This means that Integer of 1 is always the same object but Integer of 2000 will always be different object.

This experiment shows that '==' return true when the objects are the same. In case of '1' they are the same number and it returns true. But in case of '2000' autoboxed to be different objects so it returns false.

The experiment also shows that '==' does not use equals() or hashCode().

Hope this helps.