For example, I am having a column storing data like this.
Apple 12.5.126.40 Smite Abby 127.0.0.1 56.5.4.8 9876543210 Notes
How to select ou
This may not be the most efficient way, and it's not technically regex, but it should work:
SELECT col1 FROM t1 WHERE col1 LIKE '%.%.%.%';