Server returning 403 for url openStream()

Question

import java.net.URL;
import java.io.*;
import java.net.MalformedURLException;
import java.util.logging.Level;
import java.util.logging.Logger;
public class Test {
           


        

Answer 1

Your mistake is swallowing the exception.

When I run my code, I get an HTTP 403 - "forbidden". The web server won't allow you to do this.

My code works perfectly for http://www.yahoo.com.

Here's how I do it:

package url;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.Reader;
import java.net.URL;

/**
 * UrlReader
 * @author Michael
 * @since 3/20/11
 */
public class UrlReader {

    public static void main(String[] args) {
        UrlReader urlReader = new UrlReader();

        for (String url : args) {
            try {
                String contents = urlReader.readContents(url);
                System.out.printf("url: %s contents: %s\n", url, contents);
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
    }


    public String readContents(String address) throws IOException {
        StringBuilder contents = new StringBuilder(2048);
        BufferedReader br = null;

        try {
            URL url = new URL(address);
            br = new BufferedReader(new InputStreamReader(url.openStream()));
            String line = "";
            while (line != null) {
                line = br.readLine();
                contents.append(line);
            }
        } finally {
            close(br);
        }

        return contents.toString();
    }

    private static void close(Reader br) {
        try {
            if (br != null) {
                br.close();
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}