import java.net.URL;
import java.io.*;
import java.net.MalformedURLException;
import java.util.logging.Level;
import java.util.logging.Logger;
public class Test {
This is an old post but if people wanted to know how this works.
a 403 means acces-denied. There is a work around for this. If you want to able to do this you have to set a user agant parameter to 'fool' the website
This is how my old method looked like:
private InputStream read() {
try {
return url.openStream();
}
catch (IOException e) {
String error = e.toString();
throw new RuntimeException(e);
}
}
Changed it to: (And it works for me!)
private InputStream read() {
try {
HttpURLConnection httpcon = (HttpURLConnection) url.openConnection();
httpcon.addRequestProperty("User-Agent", "Mozilla/4.0");
return httpcon.getInputStream();
} catch (IOException e) {
String error = e.toString();
throw new RuntimeException(e);
}
}