Make Python unittest show AssertionError but no Traceback

Question

I have looked at the other related questions here but have not found my answer. I would like to simplify the output of my Python (2.7) unittests. Trying sys.tracebackl

Answer 1

The trick is to catch the exception, strip out the bits that aren't needed and throw it again...

Based on this answer - the following code works...

#!/usr/bin/python -E
import unittest
import os
import sys

class TestSequense(unittest.TestCase):
    pass

def test_dir_exists(dir):
    def test(self):
       try:
           self.assertTrue(os.path.isdir(dir),"ERROR: " + dir + " is not a directory")
       except:
           # Remove traceback info as we don't need it
           unittest_exception = sys.exc_info()
           raise unittest_exception[0], unittest_exception[1], unittest_exception[2].tb_next
    return test

if __name__ == '__main__':
    test = test_dir_exists("/something/not/set/correctly")
    setattr(TestSequense, "test_path",  test)
    unittest.main()

And generates the following...

./simple_unittest.py
F
======================================================================
FAIL: test_path (__main__.TestSequense)
----------------------------------------------------------------------
AssertionError: ERROR: /something/not/set/correctly is not a directory

----------------------------------------------------------------------
Ran 1 test in 0.000s