AWK to print every nth line from a file

Question

i want to print every Nth line of a file using AWK. i tried modifying the general format :-

awk \'0 == NR % 4\' results.txt

to:-

Answer 1

How about this:

awk -v n="$ct" '0 == NR % n' results.txt

or a bit shorter

awk -v n="$ct" '!(NR % n)' results.txt