Efficient way to convert Scala Array to Unique Sorted List

Question

Can anybody optimize following statement in Scala:

// maybe large
val someArray = Array(9, 1, 6, 2, 1, 9, 4, 5, 1, 6, 5, 0, 6) 

// output a sorted list whic         


        

Answer 1

How about adding everything to a sorted set?

val a = scala.collection.immutable.SortedSet(someArray filter (0 !=): _*)

Of course, you should benchmark the code to check what is faster, and, more importantly, that this is truly a hot spot.