Double.TryParse() input decimal separator different than system decimal separator

Question

I have a source XML that uses a dot (\".\") as a decimal separator and I am parsing this on a system that uses a comma (\",\") as a decimal separator.

As a result,

Answer 1

double.TryParsehas an overload taking an IFormatProvider. Use a coresponding CultureInfo, in your case CultureInfo.InvariantCulture can be used.