Given a start and end date, create an array of the dates between the two

Question

Right now, I have this on my page:

Answer 1

This worked for me too:

$("#hfEventStartDate").val(new Date - 24 * 3600 * 1000 * 7 - 1);
$("#hfEventEndDate").val(new Date - 0);

function getAllDays() {
    var s = new Date($('#hfEventStartDate').val() - 0);
    var e = new Date($('#hfEventEndDate').val() - 0);
    var a = [];
    while(s <= e) {
        a.push(new Date(s));
        s.setDate(s.getDate() + 1);
    }

    return a;
};

alert(getAllDays().join("\n"));

Is the same code that pimvdb published with some minor changes, but it gives a different result. It took me 4 hours trying to understand why, and this is what i think happens with pimvdb code:

1 loop
a[0] = S1 = $("#hfEventStartDate").val(new Date - 24 * 3600 * 1000 * 7 - 1);
//2013-09-01

2 loop
a[0] = s1.setDate(s1.getDate() + 1); // 2013-09-02
a[1] = s2 = new Date(s1.setDate(s1.getDate() + 1)) // 2013-09-02

3 loop
a[0] = s1; // 2013-09-02
a[1] = s2.setDate(s2.getDate() + 1); // 2013-09-03
a[2] = s3 = new Date(s2.setDate(s2.getDate() + 1)) // 2013-09-03

and so on...

I'm not sure if this was deliberately intended by pimvdb but his code lefts out the starting day, which in my example would be 2013-09-01. But even if it was intended, why not leaving out the last day as well? at least that's what while(s < e) seemed intended for, but the last day is included in the final array.

I'm sorry I may be wrong, I have never worked with object orientated programing, but trying to understand why a[0] was getting changed on the second loop after already been assigned on the fist one made me absolutely insane. Hope I'm not so wrong. Thank you.