I am using the following code:
downloadlink = re.findall(\"http://uploadir.com/u/(.*)\\b\", str(downloadhtml))
However, when I pass it the
Get in the habit of making all regex patterns with raw strings:
In [16]: re.findall("http://uploadir.com/u/(.*)\b", '')
Out[16]: []
In [17]: re.findall(r"http://uploadir.com/u/(.*)\b", '')
Out[17]: ['bb41c5b3']
The difference is due to \b being interpreted differently:
In [18]: '\b'
Out[18]: '\x08'
In [19]: r'\b'
Out[19]: '\\b'
'\b' is an ASCII Backspace, while r'\b' is a string composed of the two characters, a backslash and a b.