Simplest way to get current time in current timezone using boost::date_time?

Question

If I do date +%H-%M-%S on the commandline (Debian/Lenny), I get a user-friendly (not UTC, not DST-less, the time a normal person has on their wristwatch) time p

Answer 1

While this is not using boost::date_time it's relatively easy with boost::locale, which is quite more adapted for this task. As your need is simply getting a formatted time from the current locale.

IMHO boost::date_time should be used when you deal with softwares like gantt/planning computations, were you have alot of date_time arithmetic. But simply for using time and doing some arithmetic on it, you will faster success with boost::locale.

#include 
#include 

using namespace boost;

int main(int argc, char **argv) {
   locale::generator gen;
   std::locale::global(gen(""));

   locale::date_time now;
   std::cout.imbue(std::locale());       
   std::cout << locale::as::ftime("%H-%M-%S") << now << std::endl;

   return 0;
}

Right now it should output : 15-45-48. :)