Is sizeof(T) == sizeof(int)?

Question

I\'ve been poring over the draft standard and can\'t seem to find what I\'m looking for.

If I have a standard-layout type

struct T {
   unsigned hand         


        

Answer 1

I am used to Borland environments and for them:

T is a struct in your case so sizeof(T) is size of struct

• that depends on #pragma pack and align setting of your compiler
• so sometimes it can be greater than sizeof(unsigned) !!!

for the same reason if you have 4Byte struct (uint32) and 16Byte allign

• struct T { uint32 u; };
• then T a[100] is not the same as uint32 a[100];
• because T is uint32 + 12 Byte empty space !!!