sizeof behaving unexpectedly

Question

Consider the following code:

  #include 
  int main(void)
  {
    int a[10];
    printf(\"%d\",(int)sizeof(a)); //prints 10*sizeof(int) (40 on         


        

Answer 1

Nope, in the second case the argument is interpreted as an int* pointer which happens to also have size equal to 4 on your machine.