How to avoid decay with template parameter deduction

Question

Simplified:

// CHAR_TYPE == char, wchar_t, ...
template 
void Foo(CHAR_TYPE const (&value)[CHAR_COUNT]) no         


        

Answer 1

One idea that works is to remove the pointer and simply have T instead, with a std::enable_if_t::value> guard. Simplified example below:

#include 
#include 

template
void f(T const (&) [N])
{
    std::cout << __PRETTY_FUNCTION__ << std::endl;
}

template::value>* = nullptr >
void f(T)
{
    std::cout << __PRETTY_FUNCTION__ << std::endl;
}

int main()
{
    const char* str = "test";
    char str2[]{"test2"};

    f(str);
    f(str2);
}

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