List of options: equivalent of sequence in Scala?

Question

What is the equivalent of Haskell\'s sequence in Scala? I want to turn list of options into an option of list. It should come out as None if any of the options

Answer 1

This is very simple with a for comprehension:

val x : Option[String] = Option("x")
val y : Option[String] = Option("y")
val z : Option[String] = None

// Result -> a: Option[List[String]] = None    
val a = for {
  x <- x
  y <- y
  z <- z
} yield List(x,y,z)    

// Result -> b: Option[List[String]] = Some(List(x, y))    
val b = for {
  x <- x
  y <- y
} yield List(x,y)