Does Unary + operator do type conversions?

Question

Till now I was believing that there is no use of unary + operator.

But then I came across with following example:

char ch;
short sh;
in         


        

Answer 1

It's not sizeof, it's the unary + itself. The operands of unary + undergo "the usual arithmetic conversions". See, e.g., this other answer involving ordinary addition.