OSError: [Errno 22] Invalid argument in subprocess

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谎友^
谎友^ 2021-01-04 03:59

Python 3.3.3 Windows 7

Here is the full stack:
Traceback (most recent call last):
  File \"Blah\\MyScript.py\", line 578, in Call
    output = process.commun         


        
3条回答
  •  日久生厌
    2021-01-04 04:41

    The command (args) might be incorrect for OS that you're using. Try to sanitize them (check / pass through only allowed characters).

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