How to extract the file name from a file path?

Question

I have the following code:

os.listdir(\"staging\")

# Seperate filename from extension
sep = os.sep

# Change the casing
for n in os.listdir(\"staging\"):
           


        

Answer 1

This article here worked out just fine for me

import os
inputFilepath = 'path/to/file/foobar.txt'
filename_w_ext = os.path.basename(inputFilepath)
filename, file_extension = os.path.splitext(filename_w_ext)
#filename = foobar
#file_extension = .txt

path, filename = os.path.split(path/to/file/foobar.txt)
# path = path/to/file
# filename = foobar.txt

Hope it helps someone searching for this answer