Python: How to generate a 12-digit random number?

Question

In Python, how to generate a 12-digit random number? Is there any function where we can specify a range like random.range(12)?

import random
ran         


        

Answer 1

Do random.randrange(10**11, 10**12). It works like randint meets range

From the documentation:

randrange(self, start, stop=None, step=1, int=, default=None, maxwidth=9007199254740992L) method of random.Random instance
    Choose a random item from range(start, stop[, step]).

    This fixes the problem with randint() which includes the
    endpoint; in Python this is usually not what you want.
    Do not supply the 'int', 'default', and 'maxwidth' arguments.

This is effectively like doing random.choice(range(10**11, 10**12)) or random.randint(10**1, 10**12-1). Since it conforms to the same syntax as range(), it's a lot more intuitive and cleaner than these two alternatives

If leading zeros are allowed:

"%012d" %random.randrange(10**12)