Thread with Lambda expression

Question

I have an error at line 42 and 43 : Thread t1=new Thread(()->prod.test()); , Thread t2=new Thread(()->cons.test()); Unhandled exception t

Answer 1

You have created a functional interface Predicate whose method is declared to throw an InterruptedException, which is a checked exception. However, you call test() in the body of a lambda expression as the parameter to the Thread constructor that takes a Runnable, whose run() method is not declared to throw any checked exceptions. Therefore, because the exception is not caught in the body, a compiler error occurs.

Incidentally, it may be confusing to name your own interface Predicate, because of the built-in functional interface java.util.function.Predicate whose functional method returns a boolean.

Because run() can't throw an Exception, you must catch the exception and handle it. You might log the exception and its stack trace. You might wrap the exception in a RuntimeException. Either way, catching the checked exception will allow the code to compile. Example:

Thread t1 = new Thread(() -> {
    try {
        prod.test();
    } catch (InterruptedException e) {
        // handle: log or throw in a wrapped RuntimeException
        throw new RuntimeException("InterruptedException caught in lambda", e);
    }
});