Why does a narrowing conversion warning appear only in case of list initialization?

Question

I have the following code:

class A
{
    public:
        A(const unsigned int val) : value(val) {}

        unsigned int value;
};

int main()
{
    int val          


        

Answer 1

The reason behind the warning is already explained by other answers.

This is how to fix this warning/error. Create a constructor which takes initializer_list as argument.

A(std::initializer_list l) : value(*(l.begin())) { 
    cout << "constructor taking initializer list called\n";
}