Answer found here by a minimal amount of web searching:
Short answer: cout is interpreting the object as a bool due to the volatile qualifier. It's a quirk of overloading for the << operator.
Long answer: A volatile pointer can't be converted to a non-volatile pointer without an explicit cast, so neither the char* nor the void* overload can be used when the << operator is called. There's no volatile qualified overload, and the closest match is the bool overload, thus your array is interpreted as a boolean value rather than an address or a string.
You can fix it a number of ways, but an explicit cast is probably what you wanted:
std::cout<< (char*)test <
(Personally I would cast to const char*.)
