Round down datetime to previous hour

Question

How to round down datetime to previous hour? for example:

print datetime.now().replace(microsecond=0)
>> 2017-01-11 13:26:12.0

round

Answer 1

from datetime import datetime, timedelta

n = datetime.now() - timedelta(hours=1)
new_date = datetime(year=n.year, month=n.month, day=n.day, hour=n.hour)