How to get rightmost 10 places of a string in oracle

Question

I am trying to fetch an id from an oracle table. It\'s something like TN0001234567890345. What I want is to sort the values according to the right most 10 posit

Answer 1

codaddict's solution works if your string is known to be at least as long as the length it is to be trimmed to. However, if you could have shorter strings (e.g. trimming to last 10 characters and one of the strings to trim is 'abc') this returns null which is likely not what you want.

Thus, here's the slightly modified version that will take rightmost 10 characters regardless of length as long as they are present:

select substr(colName, -least(length(colName), 10)) from tableName;