How to get rightmost 10 places of a string in oracle

Question

I am trying to fetch an id from an oracle table. It\'s something like TN0001234567890345. What I want is to sort the values according to the right most 10 posit

Answer 1

You can use SUBSTR function as:

select substr('TN0001234567890345',-10) from dual;

Output:

4567890345