Function pointers with default parameters in C++

Question

How does C++ handle function pointers in relation to functions with defaulted parameters?

If I have:

void foo(int i, float f = 0.0f);
void bar(int i         


        

Answer 1

Both foo() and bar() can only be assigned to func_ptr2.

§8.3.6/2:

A default argument is not part of the type of a function. [Example:

int f(int = 0);

void h() {
    int j = f(1);
    int k = f(); // OK, means f(0)
}

int (*p1)(int) = &f; 
int (*p2)() = &f; // error: type mismatch

--end example]