Find value from one csv in another one (like vlookup) in bash (Linux)

Question

I have already tried all options that I found online to solve my issue but without good result.

Basically I have two csv files (pipe separated):

file1.

Answer 1

This will work, but since the input files must be sorted, the output order will be affected:

join -t '|' -1 7 -2 1 -o 2.3 <(sort -t '|' -k7,7 file1.csv) <(sort -t '|' -k1,1 file2.csv)

The output would look like:

2200
2200
2400

which is useless. In order to have a useful output, include the key value:

join -t '|' -1 7 -2 1 -o 0,2.3 <(sort -t '|' -k7,7 file1.csv) <(sort -t '|' -k1,1 file2.csv)

The output then looks like this:

CORKCOR|2200
CORKKIN|2200
MAYOBAN|2400

Edit:

Here's an AWK version:

awk -F '|' 'FNR == NR {keys[$7]; next} {if ($1 in keys) print $3}' file1.csv file2.csv

This loops through file1.csv and creates array entries for each value of field 7. Simply referring to an array element creates it (with a null value). FNR is the record number in the current file and NR is the record number across all files. When they're equal, the first file is being processed. The next instruction reads the next record, creating a loop. When FNR == NR is no longer true, the subsequent file(s) are processed.

So file2.csv is now processed and if it has a field 1 that exists in the array, then its field 3 is printed.