How to print the address value of a pointer in a C program?

Question

I\'m trying to learn how to use the pointer in a C program; my example is as follows:

   #include 
   #include 
   
   int mai         


        

Answer 1

p is the conversion specifier to print pointers. Use this.

int a = 42;

printf("%p\n", (void *) &a);

Remember that omitting the cast is undefined behavior and that printing with p conversion specifier is done in an implementation-defined manner.