typedef a function pointer type

Question

I want to declare a pointer type which point to a function, so I try:

typedef void (*print)(void); works perfect

void (*print)(void);

Answer 1

The correct way is:

typedef void (*print_function_ptr)(void)

and its usage for variable/parameter declaration is:

print_function_ptr p;

1. You don't need a typedef to declare a variable. You can directly write void (*p)(void) to declare a variable p pointing to a function taking void and returning void. However to declare a type alias / name for a pointer to function, typedef is the tool.

2. It does not mean anything it is not a valid C syntax.

3. Because it is not how C works. Typedefs in C mimics how variables are declared or defined.