Concept of bit field

Question

struct A
{
 int a:2;
 int b:3;
 int c:3;
};

int main()
{
 struct A p = {2,6,1};
 printf(\"\\n%d\\n%d\\n%d\\n\",p.a,p.b,p.c);
 return 0;
}    

Outp

Answer 1

I get -2 -2 1 with my C compiler. The problem is that your bit fields are too small for the numbers you are trying to store. In the first two cases, the leftmost bits are 1's, so they are interpreted as negative numbers. To fix this, either:

1. Make your bit fields larger
2. Declare your bit fields as unsigned ints instead of ints
3. Cast to unsigned int before printing and use %u to print.