Input with char pointer vs. char array

Question

consider the code

#include
int main(void)
{
   char* a;
   scanf(\"%s\",a);//&a and &a[0] give same results-crashes 
   printf(\"%s\",         


        

Answer 1

In you first code, a is an uninitialized pointer to char. You are trying to write to non-allocated memory or reserved memory.

You need to allocate memory for the input string with malloc().

---

int main(void) {
  char* s;
  /* ... */
  s = malloc(100 * sizeof(*s));
  if (s == NULL) {
    return 1;
  /* ... */
}