This question relates to those parts of the KenKen Latin Square puzzles which ask you to find all possible combinations of ncells numbers with values x such that 1 <= x &
Here a simple solution in C/C++:
const int max = 6;
int sol[N_CELLS];
void enum_solutions(int target, int n, int min) {
if (target == 0 && n == 0)
report_solution(); /* sol[0]..sol[N_CELLS-1] is a solution */
if (target <= 0 || n == 0) return; /* nothing further to explore */
sol[n - 1] = min; /* remember */
for (int i = min; i <= max; i++)
enum_solutions(target - i, n - 1, i);
}
enum_solutions(12, 4, 1);