substituting xml values programmatically with scala

Question

I\'m writing a tool to update some xml files (pom.xml in this case) with scala because the effort it would take in java is significantly higher than (in theory) it is with s

Answer 1

You really should take a look at other questions on Stack Overflow about modifying XML. Look at the "Related" links to the right.

Here:

scala> 
     |     foo
     |     bar
     |     1.0-SNAPSHOT
     | 
res0: scala.xml.Elem =

    foo
    bar
    1.0-SNAPSHOT


scala> new scala.xml.transform.RewriteRule {
     |   override def transform(n: Node): Seq[Node] = n match {
     |     case {v} if v.text contains "SNAPSHOT" => {v.text.split("-")(0)}
     |     case elem: Elem => elem copy (child = elem.child flatMap (this transform))
     |     case other => other
     |   }
     | } transform res0
res9: Seq[scala.xml.Node] =

    foo
    bar
    1.0