How to write a function wrapper for cout that allows for expressive syntax?

Question

I\'d like to wrap std::cout for formatting, like so:

mycout([what type?] x, [optional args]) {
    ... // do some formatting on x first
    std:         


        

Answer 1

This comes easy with variadic template arguments:

template 
void print(T t)
{
    std::cout << t;
}

template 
void print(T t, Args... args)
{
    std::cout << t << std::endl;
    print(args...);
}

int main()
{
    std::cout << std::boolalpha;
    print(3, 's', true, false);
}

Output:

3
s
true
false

Live Demo