Substitution with sed + bash function

Question

my question seems to be general, but i can\'t find any answers.

In sed command, how can you replace the substitution pattern by a value returned by a simple bash fun

Answer 1

sed -e 's#[0-3][0-9]/[0-1][0-9]/[0-9][0-9]#& $(parseDates &)#' myfile |
while read -r line; do
    eval echo "$line"
done