Substitution with sed + bash function

Question

my question seems to be general, but i can\'t find any answers.

In sed command, how can you replace the substitution pattern by a value returned by a simple bash fun

Answer 1

You can glue together a sed-command by ending a single-quoted section, and reopening it again.

sed -n 's|[0-3][0-9]/[0-1][0-9]/[0-9][0-9]|& '$(parseDates)' &|p' datefile

However, in contrast to other examples, a function in bash can't return strings, only put them out:

function parseDates(){
    # Some process here with $1 (the pattern found)
    echo dateParsed
}