Opening and reading an excel .xlsx file in python

Question

I\'m trying to open an excel .xlsx file with python but am unable to find a way to do it, I\'ve tried using pandas but it\'s wanting to use a library called NumPy I\'ve trie

Answer 1

Maybe you could export your .xlsx to a .csv file?

Then you could try:

import csv
with open('file.csv','rb') as file:
    contents = csv.reader(file)
    [x for x in contents]

This may be useful: http://docs.python.org/2/library/csv.html#csv.reader

Hope that helps!

EDIT:

If you want to locate a spectific cell, such as F13, you could make a nested list like a matrix and them refer to each element:

import csv
with open('file.csv','rb') as file:
    contents = csv.reader(file)
    matrix = list()
    for row in contents:
        matrix.append(row)

And then access F13 with matrix[5][12].

P.S.: I did not test this. If "row" is a list with each cell as an element, you keep appending all lines to the matrix, so the first index is row number and the second is the column number.