How to set the GnuPG home directory within the GnuPG Python binding?

Question

When trying to initialize the GnuPG binding in Python, I\'m getting an error message

TypeError: __init__() got an unexpected keyword argument \'gnupghome\'
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Answer 1

There are differnet sources when it comes to documentation, some with homedir, some with gnupghome. I dont know the time they changed it or why. Some trivial code to provide a solution to OP:

import gnupg
print gnupg.__version__
try:
    gpg = gnupg.GPG(gnupghome=homedir) 
except TypeError:
    gpg = gnupg.GPG(homedir=homedir)

Please compare the two following tracebacks. Its the same code in both cases. In one case gnupg.GPG expects 'homedir and in the other case 'gnupghome'. I am working in a virtualenv and have two different distributions of gnupg. In the virtualenv python gnupg was installed via pip:

virtualenv:

Python 2.7.9 (default, Mar  1 2015, 12:57:24) 
[GCC 4.9.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import gnupg
>>> gnupg.__version__
'2.0.2'
>>> homedir=''
>>> gpg = gnupg.GPG(homedir=homedir)
>>> gpg = gnupg.GPG(gnupghome=homedir)
Traceback (most recent call last):
  File "", line 1, in 
TypeError: __init__() got an unexpected keyword argument 'gnupghome'

global:

Python 2.7.9 (default, Mar  1 2015, 12:57:24) 
[GCC 4.9.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import gnupg
>>> gnupg.__version__
'0.3.6'
>>> homedir=''
>>> gpg = gnupg.GPG(gnupghome=homedir)
>>> gpg = gnupg.GPG(homedir=homedir)
Traceback (most recent call last):
  File "", line 1, in 
TypeError: __init__() got an unexpected keyword argument 'homedir'

I am concerned by the old gnupg version in jessie, though. Can someone elaborate on the matter?