How private method of super class are resolved?

Question

class A{ 
  private void sayA(){
     System.out.println(\"Private method of A\");
  }
  public static void main(String args[]){
      A instanceA=new B();
      ins         


        

Answer 1

InstanceA is the instance of A actually, so it can call the functions of A, but if the function is private, means that only the class declares the field can see it. eg:

public class A
{
    private void sayA(){
        System.out.println("Private method of A");
     }

    public  void funOfA(){
        System.out.println("fun of A");
     }
     public static void main(String args[]){
         A instanceA=new B();
         instanceA.sayA();
         instanceA.funOfA();
     }

}



public class B extends A
{
    public void funOfB()
    {
        System.out.println("fun of B");
    }
    public static void main(String args[]){
        A instanceA=new B();
        instanceA.funOfA();
     //  instanceA.sayA(); // This Line won't compile and run.
     //   instanceA.funOfB(); // This Line won't compile and run.
        B instanceB = new B();
        instanceB.funOfA();
        instanceB.funOfB();
     //   instanceB.sayA(); // This Line won't compile and run.
    }
}