How private method of super class are resolved?

Question

class A{ 
  private void sayA(){
     System.out.println(\"Private method of A\");
  }
  public static void main(String args[]){
      A instanceA=new B();
      ins         


        

Answer 1

It's because you're assigning B to A, so the resulting instance has access to the methods of A.

If you change to B instanceA=new B(), the subsequent line will not compile (which I believe is what you expected?).

class A{ 
  private void sayA(){
     System.out.println("Private method of A");
  }
  public static void main(String args[]){
      B instanceA=new B();
      instanceA.sayA(); # This line won't compile/run.
  }
}

class B extends A{
}