Find if every even bit is set to 0 using bitwise operators

Question

I have a 32 bit int I can only access it 8 bits at a time. I need to find out if every even bit is set to 0 and return 0 if its true and 1 otherwise.

So far I am goi

Answer 1

Just take some integer variable and store the value in it.

i= ( a & 0x55 ) + (b & 0x55 ) + ( c & 0x55 ) + (d & 0x55 )

If all the even bits are set to zero,The variable i has 0 value in it else greater than 0.and anything which is not equal to zero it is true in c.

say

 a = 10101010 & 0x55 ( 01010101) which returns zero,masking all odd bits to zero

similarly

 b & 0x55 and c & 0x55 and d & 0x55 

and if all they result to zero then variable i has zero value in it,else some other value that may be considered as True in c.