Capturing named groups in regex with re.findall

Question

When I was trying to answer this question: regex to split %ages and values in python I noticed that I had to re-order the groups from the result of findall. For example:

Answer 1

Per the OP's comment on my first answer: If you are simply trying to reorder a list of 2-tuples like this:

[('34', 'passed'), ('23', 'failed'), ('46', 'deferred')]

... to look like this, with individual elements reversed:

[('passed', '34'), ('failed', '23'), ('deferred', '46')]

There's an easy solution: use a list comprehension with the slicing syntax sequence[::-1] to reverse the order of the elements of the individual tuples:

a = [('34', 'passed'), ('23', 'failed'), ('46', 'deferred')]
b = [x[::-1] for x in a]
print b