Is it possible to write a method that takes a stringstream and have it look something like this,
void method(string st
Ah, took me a minute. Since operator<< is a free function overloaded for all ostream types, it doesn't return a std::stringstream, it returns a std::ostream like you say.
void printStringStream(std::ostream& ss)
Now clearly, general ostreams don't have a .str() member, but they do have a magic way to copy one entire stream to another:
std::cout << ss.rdbuf();
Here's a link to the full code showing that it compiles and runs fine http://ideone.com/DgL5V
If you really need a string in the function, I can think of a few solutions:
First, do the streaming seperately:
stringstream var;
var << "Text" << intVar << "More text"<
Second: copy the stream to a string (possible performance issue)
void printStringStream( ostream& t)
{
std::stringstream ss;
ss << t.rdbuf();
method(ss.str());
}
Third: make the other function take a stream too