Determine if all elements in a list are present and in the same order in another list

Question

How do I create a function sublist() that takes two lists, list1 and list2, and returns True if list1 is a s

Answer 1

def sublist(a, b):
    "if set_a is not subset of set_b then obvious answer is False"
    if not set(a).issubset(set(b)):
        return False
    n = 0
    for i in a:
        if i in b[n:]:
            "+1 is needed to skip consecutive duplicates, i.e. sublist([2,1,1],[2,1]) = False"
            "if +1 is absent then sublist([2,1,1],[2,1]) = True"
            "choose to use or not to use +1 according to your needs"
            n += b[n:].index(i) + 1
        else:
            return False
    return True